Heptomino Rectification Puzzle
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Fill a 14x14 rectangle with 28 identical P-heptominoes.
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Updated at source:
Model information
- Source
- Printables
- Category
- Puzzles & Brain-teasers
- License
- Creative Commons — Attribution
Puzzle description:
The problem of polyomino rectification is to fill a rectangle with copies of a single polyomino. For some of the polyominoes the solution with the mininmal number of pieces needs a quite large rectangle and is surprisingly difficult.
For the P-heptomino considered here the minimal rectangle has size 14x14 and consists of 28 identical P-heptominoes.
Each heptomino consists of seven solid cubies. So you also can try to built cuboids. Try to use some of the P-heptominoes to fill the following boxes:
3x3x7, 3x4x7, 3x5x7, ...
4x4x7, 4x5x7, 4x6x7, ...
5x5x7, 4x6x7, 4x7x7, ...
With more pieces you can fill any box having one side divisible by 7.
Source: https://www.math.uni-bielefeld.de/~sillke/PENTA/qu7-p3
If you can read German: Mehr Informationen gibt es in https://welt-der-geduldspiele.blogspot.com/search?q=3D-Druck
Puzzle difficulty:
The 14x14 square is of advanced difficulty.
If you do not succeed immediately, the tray contains a spare place for one heptomino.
Printing instructions:
Print the tray and 18 pieces of the G-hexomino.
Prints are fine with no supports.
I printed the puzzle in PLA at 0.1 mm layer height.
Print Settings
Printer Brand:
Prusa
Printer:
Mini
Filament: Prusament PLA black, orange
Category: Puzzles